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chujiangyu11's Question
Math
Posted 5 months ago
x<1|x|<1, 求 limx(1+x)(1+x2)(1+x3)(1+x4)(1+xn)\lim _{x \rightarrow \infty}(1+x)\left(1+x^{2}\right)\left(1+x^{3}\right)\left(1+x^{4}\right) \cdots\left(1+x^{n}\right)
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Answer from Sia
Posted 5 months ago
Solution by Steps
step 1
We start with the limit expression: limx(1+x)(1+x2)(1+x3)(1+x4)(1+xn) \lim_{x \rightarrow \infty} (1+x)(1+x^2)(1+x^3)(1+x^4) \cdots (1+x^n)
step 2
As xx approaches infinity, each term (1+xk)(1+x^k) behaves like xkx^k for large xx. Thus, we can approximate the product: limxx1+2+3++n=xn(n+1)2 \lim_{x \rightarrow \infty} x^{1+2+3+\cdots+n} = x^{\frac{n(n+1)}{2}}
step 3
Therefore, the limit simplifies to: limxxn(n+1)2= \lim_{x \rightarrow \infty} x^{\frac{n(n+1)}{2}} = \infty for n1n \geq 1
step 4
Hence, the final result is: limx(1+x)(1+x2)(1+x3)(1+x4)(1+xn)= \lim_{x \rightarrow \infty} (1+x)(1+x^2)(1+x^3)(1+x^4) \cdots (1+x^n) = \infty
Answer
The limit diverges to infinity.
Key Concept
Understanding limits involving products of polynomials as variables approach infinity.
Explanation
As xx increases, the dominant terms in the product dictate the behavior of the limit, leading to divergence.
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