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kaiwen53051's Question
Math
Posted about 2 months ago
为什么要先除1.5
帮我一步步分析这个题
Model Answer
- Principle frequencies are related to:
- Shaft (two)
- Gears (one pair)
- Bearings (one type but on shafts at different speed)
- Shaft
- Input =900rpm/60=15 Hz=900 \mathrm{rpm} / 60=15 \mathrm{~Hz}

Gear reduction ratio
- Output =(900rpm/1.5)/60=10 Hz=(900 \mathrm{rpm} / 1.5) / 60=10 \mathrm{~Hz}
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Answer from Sia
Posted about 2 months ago
Solution by Steps
step 1
The input frequency is calculated as follows: 15Hz=900rpm60 15 \, \text{Hz} = \frac{900 \, \text{rpm}}{60}
step 2
The output frequency is calculated using the gear reduction ratio: 10Hz=(900rpm/1.5)60 10 \, \text{Hz} = \frac{(900 \, \text{rpm} / 1.5)}{60}
step 3
The gear reduction ratio is given as 2416 \frac{24}{16} , which simplifies to 1.5 1.5
Answer
The input frequency is 15 Hz and the output frequency is 10 Hz.
Key Concept
Frequency calculation in mechanical systems
Explanation
The input and output frequencies are derived from the rotational speed in revolutions per minute (rpm) and adjusted for the gear reduction ratio.

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