$\int_{0}^{5}[g(x)+h(x)] d x=$

Question

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ We need to evaluate the definite integral $\int_{0}^{5}[g(x)+h(x)] \, dx$. ‖ ‖ step 2 ⋮ From the given information, the area under $g(x)$ from $0$ to $5$ is $4$. ‖ ‖ step 3 ⋮ Similarly, the area under $h(x)$ from $0$ to $5$ is $-8$. ‖ ‖ step 4 ⋮ To find the integral of $g(x) + h(x)$ from $0$ to $5$, we add the areas under $g(x)$ and $h(x)$ over this interval: $4 + (-8)$. ‖ ‖ step 5 ⋮ Simplifying, we get $4 - 8 = -4$. ‖ ∻Answer∻ ⚹ $\int_{0}^{5}[g(x)+h(x)] \, dx = -4$ ⚹ ∻Key Concept∻ ⚹Definite Integral of Sum of Functions⚹ ∻Explanation∻ ⚹The integral of the sum of two functions over an interval is the sum of the integrals of the individual functions over that interval.⚹◊What is the value of the definite integral $\int_{0}^{5} [g(x) + h(x)] dx$ based on the given information about the functions g(x) and h(x)?⍭ Generate me a similar question◊

Sia