$\frac{d}{d x}\left[-4 e^{x}-\sin (x)-9\right]=$

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∻Solution by Steps∻ ‖ step 1 ⋮ To differentiate the function $-4e^x - \sin(x) - 9$, we will apply the rules of differentiation to each term separately. ‖ ‖ step 2 ⋮ The derivative of $-4e^x$ with respect to $x$ is $-4e^x$ because the derivative of $e^x$ is $e^x$ and constants are preserved during differentiation. ‖ ‖ step 3 ⋮ The derivative of $-\sin(x)$ with respect to $x$ is $-\cos(x)$ because the derivative of $\sin(x)$ is $\cos(x)$ and we must also consider the negative sign in front of $\sin(x)$. ‖ ‖ step 4 ⋮ The derivative of a constant, $-9$, is $0$ because constants do not change and therefore have no rate of change. ‖ ‖ step 5 ⋮ Combining the results from steps 2, 3, and 4, we get the derivative of the entire function: $-4e^x - \cos(x)$. ‖ ∻Answer∻ ⚹ $-4e^x - \cos(x)$ ⚹ ∻Key Concept∻ ⚹Differentiation of Exponential and Trigonometric Functions⚹ ∻Explanation∻ ⚹The derivative of an exponential function $e^x$ is $e^x$, and the derivative of $\sin(x)$ is $\cos(x)$. Constants differentiate to zero.⚹◊What is the derivative of $-4e^{x} - \sin(x) - 9$ with respect to $x$?⍭ Generate me a similar question◊

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