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frehiwot's Question
Math
Posted 5 months ago
What is the intuitive definition of a limit, and how can it be used to determine if a limit exists?
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Answer from Sia
Posted 5 months ago
Solution by Steps
step 1
The first limit to evaluate is: limnk=1n(3+kn)41n=7815 \lim_{n \to \infty} \sum_{k=1}^{n} \left(3 + \frac{k}{n}\right)^4 \cdot \frac{1}{n} = \frac{781}{5}
step 2
The second limit is: limnk=1n(3+kn)42n=15625 \lim_{n \to \infty} \sum_{k=1}^{n} \left(3 + \frac{k}{n}\right)^4 \cdot \frac{2}{n} = \frac{1562}{5}
step 3
The third limit evaluates to: limnk=1n(3+22kn)41n=4438815 \lim_{n \to \infty} \sum_{k=1}^{n} \left(3 + \frac{22k}{n}\right)^4 \cdot \frac{1}{n} = \frac{443881}{5}
step 4
The fourth limit is: limnk=1n(3+22kn)42n=8877625 \lim_{n \to \infty} \sum_{k=1}^{n} \left(3 + \frac{22k}{n}\right)^4 \cdot \frac{2}{n} = \frac{887762}{5}
Answer
The limits evaluated are: 7815\frac{781}{5}, 15625\frac{1562}{5}, 4438815\frac{443881}{5}, and 8877625\frac{887762}{5}
Key Concept
A limit describes the behavior of a function as its input approaches a certain value.
Explanation
The limits calculated show how the sums converge to specific values as n n approaches infinity, illustrating the concept of limits in calculus.

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