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Sia

Question
Math
Posted 10 months ago

Vera is an ecologist who studies the change in the bear population of Siberia over time.

The relationship between the elapsed time, tt, in years, since Vera began studying the population, and the total number of bears, N(t)N(t), is modeled by the following function:
N(t)=2187(23)t
N(t)=2187 \cdot\left(\frac{2}{3}\right)^{t}


Complete the following sentence about the yearly rate of change of the bear population.

Every year, the bear population grows/shrinks \vee by a factor of
\square
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Answer from Sia
Posted 10 months ago
Solution by Steps
step 1
To find the yearly rate of change of the bear population, we need to calculate the derivative of the function N(t)=2187(23)tN(t) = 2187 \cdot \left(\frac{2}{3}\right)^t
step 2
The derivative of N(t)N(t) with respect to tt is N(t)=2187ln(23)(23)tN'(t) = 2187 \cdot \ln\left(\frac{2}{3}\right) \cdot \left(\frac{2}{3}\right)^t
step 3
Since ln(23)\ln\left(\frac{2}{3}\right) is negative, the derivative N(t)N'(t) will be negative for all tt. This means the bear population is decreasing over time
step 4
The factor by which the population changes each year is the base of the exponential function, 23\frac{2}{3}
Answer
Every year, the bear population shrinks by a factor of 23\frac{2}{3}.
Key Concept
Derivative of Exponential Functions
Explanation
The derivative of an exponential function abta \cdot b^t where aa and bb are constants, and tt is the variable, is found by multiplying the function by the natural logarithm of the base bb. If b<1b < 1, the function represents exponential decay, and the population decreases over time.

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