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Biology
Posted 10 months ago

Two genes RR and YY which control seed shape and seed color are located on the same chromosome 20 mC\mathrm{mC} apart. If you cross a plant with round/yellow seeds and a plant with wrinkled/green seeds, what is an expected chance of ontaining plants with wrinkled/green?
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Answer from Sia
Posted 10 months ago
Answer
The expected chance of obtaining plants with wrinkled/green seeds from this cross is dependent on the recombination frequency between the two genes.
Solution
a
Determine the parental genotypes: The plant with round/yellow seeds has the dominant alleles (RRYY), and the plant with wrinkled/green seeds has the recessive alleles (rryy)
b
Calculate recombination frequency: The genes are located 20mC20 \mathrm{mC} apart, which means there is a 20% chance of recombination between them
c
Determine gamete formation: Without recombination, the RRYY plant can only produce RY gametes, and the rryy plant can only produce ry gametes. With recombination, there is a 20% chance of producing Ry and rY gametes
d
Calculate the probability of wrinkled/green offspring: Since wrinkled/green is recessive, we need an ry gamete from both parents. The chance of an ry gamete from the RRYY parent is 10% (half of the recombination frequency), and it is 100% from the rryy parent
e
Use the product rule: The probability of an offspring being wrinkled/green is the product of the probabilities of receiving an ry gamete from each parent, which is 0.10×1.00=0.100.10 \times 1.00 = 0.10 or 10%
Key Concept
Genetic linkage and recombination frequency
Explanation
The chance of obtaining wrinkled/green seeds from the cross is calculated based on the recombination frequency between the linked genes that control seed shape and color.

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