The reaction of nitric oxide with hydrogen at 1280∘C is
2NO(g)+2H2(g)⟶N2(g)+2H2O(g)
From the following data collected at this temperature, determine (a) the rate law, (b) the rate constant, and (c) the rate of the reaction when [NO]=12.0×10−3M and
[H2]=6.0×10−3M.
\begin{tabular}{cccc}
Experiment & {[NO](M)} & {[H2](M)} & Initial Rate (M/s) \\
\hline 1 & 5.0×10−3 & 2.0×10−3 & 1.3×10−5 \\
2 & 10.0×10−3 & 2.0×10−3 & 5.0×10−5 \\
3 & 10.0×10−3 & 4.0×10−3 & 10.0×10−5
\end{tabular}
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Answer from Sia
Posted 10 months ago
Solution
1
Determine the order with respect to NO: Compare experiments 1 and 2 where the concentration of H2 is constant. Calculate the rate order with respect to NO by using the initial rates and concentrations of NO
2
Determine the order with respect to H₂: Compare experiments 2 and 3 where the concentration of NO is constant. Calculate the rate order with respect to H2 by using the initial rates and concentrations of H2
3
Write the rate law: Using the orders determined in steps 1 and 2, write the rate law expression
4
Calculate the rate constant (k): Use the given rate constant value to confirm the rate law
5
Calculate the rate of the reaction: Use the rate law and the given concentrations of NO and H2 to calculate the rate of the reaction
1 Answer
The rate law is Rate = k[NO]2[H2]
2 Answer
The rate constant (k) is 6.0×103M−2s−1
3 Answer
The rate of the reaction is 4.32×10−4M/s
Key Concept
The rate law for a reaction relates the rate of the reaction to the concentrations of the reactants and includes a rate constant (k) and reaction orders (m and n).
Explanation
The rate law is determined by comparing the initial rates and reactant concentrations from different experiments. The rate constant is a proportionality constant that relates the rate of a reaction to the concentrations of the reactants raised to their respective orders in the rate law.
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