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Question
Math
Posted 11 months ago
The greatest common divisor of positive integers m and n is 6.
The least common multiple of m and n is 126. What is the least
possible value of m + n?
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Answer from Sia
Posted 11 months ago
Solution by Steps
step 1
Given that the greatest common divisor (gcd) of m m and n n is 6 and the least common multiple (lcm) of m m and n n is 126
step 2
The product of the gcd and lcm of two numbers m m and n n is equal to the product of the numbers themselves, i.e., gcd(m,n)×lcm(m,n)=m×n \text{gcd}(m, n) \times \text{lcm}(m, n) = m \times n
step 3
Substituting the given values, we get 6×126=m×n 6 \times 126 = m \times n
step 4
Simplifying, we find m×n=756 m \times n = 756
step 5
Since m m and n n are both divisible by their gcd, which is 6, we can write m=6k m = 6k and n=6l n = 6l , where k k and l l are co-prime (since 6 is the gcd)
step 6
Substituting m=6k m = 6k and n=6l n = 6l into m×n=756 m \times n = 756 , we get 6k×6l=756 6k \times 6l = 756
step 7
Simplifying, we find k×l=21 k \times l = 21
step 8
The pairs of positive integers that multiply to 21 are (1, 21) and (3, 7)
step 9
The sum m+n m + n in terms of k k and l l is 6k+6l 6k + 6l
step 10
For the pair (1, 21), the sum is 6(1)+6(21)=6+126=132 6(1) + 6(21) = 6 + 126 = 132
step 11
For the pair (3, 7), the sum is 6(3)+6(7)=18+42=60 6(3) + 6(7) = 18 + 42 = 60
step 12
The least possible value of m+n m + n is therefore 60, corresponding to the pair (3, 7)
Answer
60
Key Concept
Product of gcd and lcm of two numbers
Explanation
The product of the gcd and lcm of two numbers is equal to the product of the numbers themselves. By finding the prime factorization of the product, we can determine the smallest possible sum of the two numbers.

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