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Question
Math
Posted 9 months ago

The function ff is defined over the real numbers except for x=0x=0. This table gives select values of ff.
\begin{tabular}{lccccccc}
xx & -0.1 & -0.01 & -0.001 & 0 & 0.001 & 0.01 & 0.1 \\
\hlinef(x)f(x) & 2.63 & 2.77 & 2.89 & undefined & 2.88 & 2.75 & 2.6
\end{tabular}

What is a reasonable estimate for limx0f(x)\lim _{x \rightarrow 0} f(x) ?
Choose 1 answer:
(A) 0
(B) 0.1
(C) 2.75
(D) 2.9
(E) The limit doesn't exist
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Answer from Sia
Posted 9 months ago
Solution by Steps
step 2
The table provides the following values for f(x)f(x): x0.10.010.00100.0010.010.1f(x)2.632.772.89undefined2.882.752.6 \begin{array}{|c|c|c|c|c|c|c|c|} \hline x & -0.1 & -0.01 & -0.001 & 0 & 0.001 & 0.01 & 0.1 \\ \hline f(x) & 2.63 & 2.77 & 2.89 & \text{undefined} & 2.88 & 2.75 & 2.6 \\ \hline \end{array}
step 3
As xx approaches 0 from both the left and the right, the values of f(x)f(x) are getting closer to a certain number
step 4
From the left (x=0.001,0.01,0.1x = -0.001, -0.01, -0.1), f(x)f(x) values are 2.89, 2.77, and 2.63 respectively. From the right (x=0.001,0.01,0.1x = 0.001, 0.01, 0.1), f(x)f(x) values are 2.88, 2.75, and 2.6 respectively
step 5
Both sides are approaching a value close to 2.75 as xx gets closer to 0
step 6
Therefore, a reasonable estimate for limx0f(x)\lim_{x \to 0} f(x) is 2.75
C
Key Concept
Limit of a function
Explanation
The limit of a function as xx approaches a certain value is the value that the function's output gets closer to as xx gets closer to that value.

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