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Question
Math
Posted 9 months ago

The base of a solid SS is the region bounded by the parabola x2=8yx^{2}=8 y and the line y=4y=4.

Cross-sections perpendicular to the yy-axis are isosceles right triangles with the hypotenuse lying in the base.

Determine the exact volume of solid SS.
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Answer from Sia
Posted 9 months ago
Solution by Steps
step 1
The base of the solid SS is the region bounded by the parabola x2=8yx^2 = 8y and the line y=4y = 4. We need to find the volume of the solid with cross-sections perpendicular to the yy-axis that are isosceles right triangles with the hypotenuse lying in the base
step 2
The length of the hypotenuse of each isosceles right triangle is the distance between the points where the parabola intersects the line y=4y = 4. Solving x2=84x^2 = 8 \cdot 4, we get x2=32x^2 = 32, so x=±32=±42x = \pm \sqrt{32} = \pm 4\sqrt{2}. Thus, the length of the hypotenuse is 242=822 \cdot 4\sqrt{2} = 8\sqrt{2}
step 3
For an isosceles right triangle, the relationship between the hypotenuse hh and the legs aa is h=a2h = a\sqrt{2}. Therefore, a=h2=822=8a = \frac{h}{\sqrt{2}} = \frac{8\sqrt{2}}{\sqrt{2}} = 8
step 4
The area of each cross-sectional triangle is 12aa=1288=32\frac{1}{2} \cdot a \cdot a = \frac{1}{2} \cdot 8 \cdot 8 = 32
step 5
To find the volume of the solid, we integrate the area of the cross-sections along the yy-axis from y=0y = 0 to y=4y = 4: 0432dy\int_0^4 32 \, dy
step 6
Evaluating the integral, we get 3204dy=32[y]04=32(40)=12832 \int_0^4 dy = 32 [y]_0^4 = 32 \cdot (4 - 0) = 128
Answer
The exact volume of the solid SS is 128128 cubic units.
Key Concept
Volume of a solid with known cross-sectional area
Explanation
To find the volume of a solid with a known cross-sectional area, integrate the area of the cross-sections along the axis perpendicular to the cross-sections.

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