Solve for $a$. Reduce any fractions to lowest terms. Don't round your answer, and don't use mixed fractions.
$$
60 a+64 \geq 80 a-92
$$

Question

Solve for $a$. Reduce any fractions to lowest terms. Don't round your answer, and don't use mixed fractions.
$$
60 a+64 \geq 80 a-92
$$

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ Start with the given inequality: $60a + 64 \geq 80a - 92$. ‖ ‖ step 2 ⋮ Subtract $60a$ from both sides to get: $64 \geq 20a - 92$. ‖ ‖ step 3 ⋮ Add $92$ to both sides to isolate the term with $a$: $156 \geq 20a$. ‖ ‖ step 4 ⋮ Divide both sides by $20$ to solve for $a$: $a \leq \frac{156}{20}$. ‖ ‖ step 5 ⋮ Reduce the fraction to lowest terms: $a \leq \frac{39}{5}$. ‖ ∻Answer∻ ⚹ $a \leq \frac{39}{5}$ ⚹ ∻Key Concept∻ ⚹Solving inequalities⚹ ∻Explanation∻ ⚹To solve the inequality for $a$, we isolate $a$ on one side by performing inverse operations, such as subtracting and adding terms on both sides, and finally dividing by the coefficient of $a$. The inequality sign remains the same because we did not multiply or divide by a negative number.⚹◊What is the solution for $a$ in the inequality $60a + 64 \geq 80a - 92$ after reducing fractions to lowest terms without rounding?⍭ Generate me a similar question◊

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