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haolun's Question
Math
Posted 10 months ago
Question 9
Find the intersection of the three planes:
x+y+2z=23xy+14z=6x+2y=5
\begin{array}{l}
x+y+2 z=-2 \\
3 x-y+14 z=6 \\
x+2 y=-5
\end{array}
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Answer from Sia
Posted 10 months ago
Solution by Steps
step 1
To find the intersection of the three planes, we can solve the system of equations given by the plane equations
step 2
The system of equations is: {x+y+2z=23xy+14z=6x+2y=5\begin{cases} x + y + 2z = -2 \\ 3x - y + 14z = 6 \\ x + 2y = -5 \end{cases}
step 3
From the asksia-ll calculation list, we have the partial solution: y=x252y = -\frac{x}{2} - \frac{5}{2} and z=14x4z = \frac{1}{4} - \frac{x}{4}
step 4
Substitute yy and zz from step 3 into the first equation x+y+2z=2x + y + 2z = -2 to find the value of xx
step 5
Solving for xx gives us x=3x = -3
step 6
Substitute x=3x = -3 back into the equations for yy and zz to find their values
step 7
We get y=3252=3252=1y = -\frac{-3}{2} - \frac{5}{2} = \frac{3}{2} - \frac{5}{2} = -1 and z=1434=14+34=1z = \frac{1}{4} - \frac{-3}{4} = \frac{1}{4} + \frac{3}{4} = 1
Answer
The intersection of the three planes is the point (3,1,1)(-3, -1, 1).
Key Concept
Solving a system of linear equations
Explanation
To find the intersection of three planes, we solve the system of equations represented by the planes. The solution gives us the coordinates of the intersection point.

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