Point $Q^{\prime}(3,2)$ is the image of $Q(6,4)$ under a translation.
Determine the translation.
Use non-negative numbers.

A translation by $\square$ units to the right/left $\square$ and $\square$ units
up/down

Question

Point $Q^{\prime}(3,2)$ is the image of $Q(6,4)$ under a translation.
Determine the translation.
Use non-negative numbers.

A translation by $\square$ units to the right/left $\square$ and $\square$ units
up/down

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ Identify the original coordinates of point $Q$ and the translated coordinates of point $Q'$. ‖ ‖ step 2 ⋮ Calculate the change in the $x$-coordinate from $Q$ to $Q'$ by subtracting the $x$-coordinate of $Q'$ from the $x$-coordinate of $Q$: $6 - 3$. ‖ ‖ step 3 ⋮ Calculate the change in the $y$-coordinate from $Q$ to $Q'$ by subtracting the $y$-coordinate of $Q'$ from the $y$-coordinate of $Q$: $4 - 2$. ‖ ‖ step 4 ⋮ Determine the direction of the translation for both $x$ and $y$ coordinates based on the signs of the changes calculated in steps 2 and 3. ‖ ∻Answer∻ ⚹ The translation is 3 units to the left and 2 units down. ⚹ ∻Key Concept∻ ⚹Translation in the Coordinate Plane⚹ ∻Explanation∻ ⚹To find the translation that maps point $Q$ to point $Q'$, we subtract the coordinates of $Q'$ from the coordinates of $Q$. The result gives us the magnitude and direction of the translation. A positive result indicates a translation to the right (for $x$) or up (for $y$), while a negative result indicates a translation to the left (for $x$) or down (for $y$). In this case, the translation is to the left and down because the changes in coordinates are negative.⚹◊What is the formula for the translation mapping point Q to point Q'?⍭ Generate me a similar question◊

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