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Question
Math
Posted 12 months ago

On the following unit circle, θ\theta is in radians and tan(θ)=0.990.1=9.9\tan (\theta)=\frac{-0.99}{0.1}=-9.9.

Without a calculator, evaluate the following expressions to the nearest hundredth or as an exact ratio.
\begin{tabular}{ll} 
Expression & Value \\
\hline tan(π+θ)\tan (\pi+\theta) & \square \\
tan(2π+θ)\tan (2 \pi+\theta) & \square
\end{tabular}
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Answer from Sia
Posted 12 months ago
Solution by Steps
step 1
Recall the periodic properties of the tangent function, specifically that tan(θ)\tan(\theta) is periodic with period π\pi. This means that tan(θ+π)=tan(θ)\tan(\theta + \pi) = \tan(\theta)
step 2
Apply the periodic property to tan(π+θ)\tan(\pi + \theta). Since tan(θ)=9.9\tan(\theta) = -9.9, we have tan(π+θ)=tan(θ)=9.9\tan(\pi + \theta) = \tan(\theta) = -9.9
step 3
Similarly, apply the periodic property to tan(2π+θ)\tan(2\pi + \theta). Since tan(θ)\tan(\theta) is periodic with period π\pi, tan(2π+θ)=tan(θ)=9.9\tan(2\pi + \theta) = \tan(\theta) = -9.9
[question 1] Answer
tan(π+θ)=9.9\tan(\pi + \theta) = -9.9
tan(2π+θ)=9.9\tan(2\pi + \theta) = -9.9
Key Concept
Periodicity of the Tangent Function
Explanation
The tangent function has a period of π\pi, which means that tan(θ+nπ)=tan(θ)\tan(\theta + n\pi) = \tan(\theta) for any integer nn. This property allows us to find the value of the tangent function for angles that differ by an integer multiple of π\pi.

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