In an experimental setup, a novel organic compound, L, with a molecular formula $\mathrm{C} 7 \mathrm{H} 8 \mathrm{O} 2$, is synthesized. This compound exhibits unique reactivity patterns: it forms pink complex with $\mathrm{FeCl} 3$ solution, suggesting phenolic $\mathrm{OH}$ groups, and it gives a positive iodoform test, indicative of a methyl ketone group. Additionally, L does not decolorize bromine water, implying it does not have carbon-carbon double bonds. Based on these observations and the principles of organic chemistry, what is the most likely structure for compound L? Options: a) 4-hydroxyacetophenone b) 2 hydroxybenzoic acid (salicylic acid) c) 3-hydroxybenzaldehyde d) 1,4-dihydroxy-2butanone

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***A*** ∻Key Concept∻ ⚹Identification of functional groups through chemical tests⚹ ∻Explanation∻ ⚹The compound L forms a pink complex with $\mathrm{FeCl}_3$ indicating the presence of a phenolic $\mathrm{OH}$ group, and gives a positive iodoform test, which is characteristic of a methyl ketone group. The absence of reaction with bromine water suggests there are no carbon-carbon double bonds. Among the options, 4-hydroxyacetophenone has both a phenolic $\mathrm{OH}$ group and a methyl ketone structure, which aligns with the given reactivity patterns.⚹◊What structural features of compound L lead to its positive iodoform test?⍭ Generate me a similar question◊

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