Asksia AI LOGO

Sia

Question
Math
Posted 11 months ago
If x2+bx+b+3=0x^{2}+b x+b+3=0 has roots of the form b±52\frac{-b \pm \sqrt{5}}{2}, where b>0b>0, then b=m+nb=m+\sqrt{n} for positive integers m,nm, n. Find m+nm+n.
Sign in to unlock the answer
Answer from Sia
Posted 11 months ago
Solution by Steps
step 1
Given the quadratic equation x2+bx+b+3=0 x^{2} + bx + b + 3 = 0 and its roots b±52 \frac{-b \pm \sqrt{5}}{2} , we can use the quadratic formula to find the value of b b
step 2
The quadratic formula for the roots of ax2+bx+c=0 ax^2 + bx + c = 0 is x=b±b24ac2a x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} . Comparing this with the given roots, we have b24(b+3)=5 \sqrt{b^2 - 4(b + 3)} = \sqrt{5}
step 3
Squaring both sides of the equation b24(b+3)=5 \sqrt{b^2 - 4(b + 3)} = \sqrt{5} gives b24b12=5 b^2 - 4b - 12 = 5
step 4
Solving b24b12=5 b^2 - 4b - 12 = 5 for b b gives b24b17=0 b^2 - 4b - 17 = 0
step 5
The solutions for b b are b=221 b = 2 - \sqrt{21} and b=2+21 b = 2 + \sqrt{21} . Since b>0 b > 0 , we take the positive solution b=2+21 b = 2 + \sqrt{21}
step 6
We have b=m+n b = m + \sqrt{n} where m=2 m = 2 and n=21 n = 21
step 7
To find m+n m + n , we add m m and n n to get 2+21 2 + 21
Answer
m+n=23 m + n = 23
Key Concept
Quadratic Equations and Roots
Explanation
The roots of a quadratic equation can be found using the quadratic formula. By comparing the given roots with the formula, we can solve for the unknown coefficient b b . Once b b is found, we can express it in the form b=m+n b = m + \sqrt{n} and find the sum m+n m + n .

Not the question you are looking for? Ask here!

Enter question by text

Enter question by image

Unlock Smarter Learning with AskSia Super!

Join Super, our all-in-one AI solution that can greatly improve your learning efficiency.

30% higher accuracy than GPT-4o
Entire learning journey support
The most student-friendly features
Study Other Question