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Question
Chemistry
Posted 8 months ago

How many carbon atoms are on the left side of the following chemical equation?
Mg(C2H3O2)2+Na2CO32NaC2H3O2+MgCO3
\mathrm{Mg}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}+\mathrm{Na}_{2} \mathrm{CO}_{3} \rightarrow 2 \mathrm{NaC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}+\mathrm{MgCO}_{3}

\square carbon atoms
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Answer from Sia
Posted 8 months ago
Solution
1
Identify the compounds on the left side of the equation: The chemical equation given is: Mg(C2H3O2)2+Na2CO32NaC2H3O2+MgCO3 \mathrm{Mg}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2} + \mathrm{Na}_{2} \mathrm{CO}_{3} \rightarrow 2 \mathrm{NaC}_{2} \mathrm{H}_{3} \mathrm{O}_{2} + \mathrm{MgCO}_{3} The compounds on the left side are Mg(C2H3O2)2\mathrm{Mg}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2} and Na2CO3\mathrm{Na}_{2} \mathrm{CO}_{3}
2
Count the carbon atoms in each compound: - In Mg(C2H3O2)2\mathrm{Mg}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}, there are 2 acetate ions, each containing 2 carbon atoms. Therefore, the total number of carbon atoms in this compound is 2×2=42 \times 2 = 4. - In Na2CO3\mathrm{Na}_{2} \mathrm{CO}_{3}, there is 1 carbonate ion containing 1 carbon atom. Therefore, the total number of carbon atoms in this compound is 11
3
Sum the total number of carbon atoms on the left side: 4 (from Mg(C2H3O2)2)+1 (from Na2CO3)=5 carbon atoms 4 \text{ (from } \mathrm{Mg}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}) + 1 \text{ (from } \mathrm{Na}_{2} \mathrm{CO}_{3}) = 5 \text{ carbon atoms}
Answer
5 carbon atoms
Key Concept
Counting atoms in chemical compounds
Explanation
To determine the number of carbon atoms on the left side of a chemical equation, identify the compounds present, count the carbon atoms in each compound, and sum them up.

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