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sally_516's Question
Math
Posted 9 months ago
Graphing sine and cosine functions
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Answer from Sia
Posted 9 months ago
Solution by Steps
step 1
We need to integrate the function 6cos(1+sin(t))6 \cos(1 + \sin(t)) from 00 to 33
step 2
The integral is given by 036cos(1+sin(t))dt\int_0^3 6 \cos(1 + \sin(t)) \, dt
step 3
Using the Asksia-LL calculator, the result of the integral is approximately 1.6335888917-1.6335888917
Answer
The integral of 6cos(1+sin(t))6 \cos(1 + \sin(t)) from 00 to 33 is approximately 1.6335888917-1.6335888917.
Key Concept
Definite Integral
Explanation
A definite integral calculates the area under a curve between two points. In this case, we integrated the function 6cos(1+sin(t))6 \cos(1 + \sin(t)) from 00 to 33.

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