Graph $y=2 \cos \left(\frac{1}{2} x\right)-1$ in the interactive widget.
Note that one moveable point always defines an extremum point in the graph and the other point always defines a neighbouring intersection with the midline.

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∻Solution by Steps∻ ‖ step 1 ⋮ To find the integral of $6 \cos(1 + \sin(t))$ from $t=3$ to $t=0$, we use the fundamental theorem of calculus. ‖ ‖ step 2 ⋮ The Asksia-LL calculator has already computed this integral and provided the result. ‖ ‖ step 3 ⋮ The result from the Asksia-LL calculator for the integral is approximately $1.6335888917$. ‖ ‖ step 4 ⋮ To complete the calculation for the second part, we add 2 to the result from step 1. ‖ ‖ step 5 ⋮ Adding 2 to the integral result gives us $1.6335888917 + 2 \approx 3.6335888917$. ‖ ∻[question 1] Answer∻ ⚹ The result of the calculation $2 + ext{(result from step 1)}$ is approximately $3.6335888917$. ⚹ ∻Key Concept∻ ⚹Integration and the fundamental theorem of calculus⚹ ∻Explanation∻ ⚹The integral of a function over an interval can be found using the fundamental theorem of calculus, and additional arithmetic operations can be applied to this result as needed.⚹◊What is the equation of the midline of the trigonometric function represented by the given graph?⍭ Generate me a similar question◊

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