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alice15609's Question
Math
Posted 9 months ago

Exercise 3
Plane Geometry (II)
Level 1
Question 1
ABCDA B C D is a parallelogram with ABDC,ADBCA B\|D C, A D\| B C as shown. The diagonal BDB D is drawn.
(a) Prove that ABDCDB\triangle A B D \equiv \triangle C D B.
(b) Hence, explain why AD=CBA D=C B and AB=CDA B=C D.
(c) What property of parallelograms have we proved?

Question 2
Prove that the opposite angles of a parallelogram are equal.
Year 9 (A1) Mathematics
Question 2*
ABCDA B C D is a quadrilateral with P,Q,RP, Q, R and SS being the midpoints of sides AB,BCA B, B C, CDC D and DAD A respectively. Prove that PBQ\triangle P B Q is similar to ABC\triangle A B C, and hence that PQACP Q \| A C. Thus prove quadrilateral PQRSP Q R S is a parallelogram.
Exercise 2
Level 3

Question-1
PQRSP Q R S is a trapezium with PQSRP Q \| S R. If A,BA, B and CC are the mid-points of SP,PRS P, P R and QRQ R respectively, prove that:
(a) ABSRA B \| S R :
(b) BCPQB C \| P Q;
(c) the points A,BA, B and CC are collinear.

Question 2*
In the figure, ABCDA B C D is a trapezium, and MNM N is parallel to ABA B and DCD C. If MNM N bisects the area ABCDA B C D, the length of MNM N, in centimetres, is
(A) a2+b22\sqrt{\frac{a^{2}+b^{2}}{2}}
(B) a2+b2a+b\frac{a^{2}+b^{2}}{a+b}
(C) ab\sqrt{a b}
(D) 2aba+b\frac{2 a b}{a+b}
(E) a+b2\frac{a+b}{2}
(AMC)
Question 1*
Let ABCDA B C D be a quadrilateral, with diagonals meeting at right angles at MM.
(a) Find expressions for AB2,BC2,CD2A B^{2}, B C^{2}, C D^{2} and AD2A D^{2} in terms of a,b,ca, b, c and dd.
(b) Hence show that AB2+CD2=BC2+AD2A B^{2}+C D^{2}=B C^{2}+A D^{2}.

Question 2*
ABCDA B C D is a quadrilateral with DAB=DCB=90\angle D A B=\angle D C B=90^{\circ}. The bisectors of ADC\angle A D C and ABC\angle A B C meet the diagonal ACA C at EE and FF respectively. Prove that DED E and BFB F are parallel.
(b) Prove that PRTSP R T S is a parallelogram.
Plane Geometry
Question 4
The diagram shows the parallelogram ABCDA B C D with diagonal ACA C. The points PP and QQ lie on this diagonal in such a way that AP=CQA P=C Q.
(a) Prove that ABPCDQ\triangle A B P \equiv \triangle C D Q.
(b) Prove that ADPCBQ\triangle A D P \equiv \triangle C B Q.
(c) Hence prove that BQDPB Q D P is a parallelogram.
(b) ABCDA B C D is a parallerogram.

Question 2
In the diagram, ABCDA B C D is a quadrilateral in which the diagonals meet at MM, with AM=MCA M=M C and BM=MDB M=M D.
(a) Prove ABMCDM\triangle A B M \equiv \triangle C D M.
(b) Hence prove that quadrilateral ABCDA B C D is a parallelogram.

Question 3
PQRSP Q R S is a parallelogram, QRTQ R T and PMTP M T are straight lines and MM is the midpoint of SR.
(a) Prove that PMSTMR\triangle P M S \equiv \triangle T M R.
Question 3
Prove that the diagonals of a parallelogram bisect each other, i.e. prove that in the parallelogram PQRSP Q R S,

Question 4
Show that ABDC,ADBCA B\|D C, A D\| B C.
Level 2

Question 1
In the diagram, ABCDA B C D is a quadrilateral with ABDCA B \| D C and AB=DCA B=D C. The diagonal BDB D is drawn. Prove that:
(a) ADB=DBC\angle A D B=\angle D B C;
Year 9 (A1) Mathematics
(b) Prove that the triangles ABCA B C and DCBD C B are congruent.
Plane Geometry (II)
(c) Deduce that ABD=DCA\angle A B D=\angle D C A.

Question 4
ABCDA B C D is a quadrilateral. The diagonals ACA C and BDB D intersect at P.AD=BCP . A D=B C and AC=BDA C=B D.
(a) Show that triangles ABCA B C and ABDA B D are congruent.
(b) Show that triangle ABPA B P is isosceles.
c) Hence show that triangle CDPC D P is isosceles.

Show that ABA B is parallel to CDC D.
Year 9 (A1) Mathematics
(b) Prove that the triangles ABCA B C and DCBD C B are congruent.
Plane Geometry (II)
(c) Deduce that ABD=DCA\angle A B D=\angle D C A.

Question 4
ABCDA B C D is a quadrilateral. The diagonals ACA C and BDB D intersect at P.AD=BCP . A D=B C and AC=BDA C=B D.
(a) Show that triangles ABCA B C and ABDA B D are congruent.
(b) Show that triangle ABPA B P is isosceles.
c) Hence show that triangle CDPC D P is isosceles.

Show that ABA B is parallel to CDC D.
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Answer from Sia
Posted 9 months ago
Solution by Steps
step 1
Given that ABCDA B C D is a parallelogram with ABDCA B \parallel D C and ADBCA D \parallel B C, and the diagonal BDB D is drawn
step 2
To prove that ABDCDB\triangle A B D \equiv \triangle C D B, we need to show that the triangles are congruent
step 3
In ABD\triangle A B D and CDB\triangle C D B, we have: - AB=CDA B = C D (opposite sides of a parallelogram are equal) - AD=BCA D = B C (opposite sides of a parallelogram are equal) - ABD=CDB\angle A B D = \angle C D B (alternate interior angles are equal because ABDCA B \parallel D C and ADBCA D \parallel B C)
step 4
By the Side-Angle-Side (SAS) congruence criterion, ABDCDB\triangle A B D \equiv \triangle C D B
step 5
Since ABDCDB\triangle A B D \equiv \triangle C D B, it follows that AD=CBA D = C B and AB=CDA B = C D
step 6
The property of parallelograms that we have proved is that the opposite sides of a parallelogram are equal
1 Answer
A
Key Concept
Congruence of Triangles
Explanation
To prove that two triangles are congruent, we can use the Side-Angle-Side (SAS) criterion, which states that if two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, then the triangles are congruent.
Solution by Steps
step 1
Given that ABCDA B C D is a quadrilateral with P,Q,R,P, Q, R, and SS being the midpoints of sides AB,BC,CD,A B, B C, C D, and DAD A respectively
step 2
To prove that PBQ\triangle P B Q is similar to ABC\triangle A B C, we need to show that the corresponding angles are equal and the sides are proportional
step 3
Since PP and QQ are midpoints, PQP Q is parallel to ACA C and PQ=12ACP Q = \frac{1}{2} A C
step 4
Therefore, PBQABC\triangle P B Q \sim \triangle A B C by the Midpoint Theorem, which states that the line segment joining the midpoints of two sides of a triangle is parallel to the third side and half as long
step 5
Since PQACP Q \parallel A C, quadrilateral PQRSP Q R S is a parallelogram because both pairs of opposite sides are parallel
2 Answer
A
Key Concept
Midpoint Theorem
Explanation
The Midpoint Theorem states that the line segment joining the midpoints of two sides of a triangle is parallel to the third side and half as long. This theorem helps in proving similarity and parallelism in quadrilaterals.

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