Divide the polynomials.
Your answer should be in the form $p(x)+\frac{k}{x}$ where $p$ is a polynomial and $k$ is an integer.
$$
\frac{6 x^{2}-4 x-3}{x}=
$$
$\square$

Question

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ To divide the polynomial $6x^2 - 4x - 3$ by $x$, we separate each term by $x$. ‖ ‖ step 2 ⋮ Dividing $6x^2$ by $x$ gives us $6x$. ‖ ‖ step 3 ⋮ Dividing $-4x$ by $x$ gives us $-4$. ‖ ‖ step 4 ⋮ Dividing $-3$ by $x$ gives us $-\frac{3}{x}$. ‖ ‖ step 5 ⋮ Combining the results from steps 2, 3, and 4, we get $6x - 4 - \frac{3}{x}$. ‖ ∻[1] Answer∻ ⚹ $6x - 4 - \frac{3}{x}$ ⚹ ∻Key Concept∻ ⚹Polynomial Long Division⚹ ∻Explanation∻ ⚹When dividing a polynomial by a monomial, each term of the polynomial is divided by the monomial separately.⚹◊What is the quotient when the polynomial $6x^2 - 4x - 3$ is divided by $x$?⍭ Generate me a similar question◊

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