Complete the recursive formula of the arithmetic sequence $14,30,46,62, \ldots$.
$d(1)=$ $\square$
$$
d(n)=d(n-1)+
$$
$\square$

Question

Complete the recursive formula of the arithmetic sequence $14,30,46,62, \ldots$.
$d(1)=$ $\square$
$$
d(n)=d(n-1)+
$$
$\square$

Accepted Answer

∻Solution by Steps∻ ‖ step 1 ⋮ Identify the first term of the arithmetic sequence. ‖ ‖ step 2 ⋮ The first term, $d(1)$, is given as 14. ‖ ‖ step 3 ⋮ Determine the common difference of the sequence. ‖ ‖ step 4 ⋮ The common difference can be found by subtracting any term from the subsequent term, for example, $30 - 14 = 16$. ‖ ‖ step 5 ⋮ Write the recursive formula using the first term and the common difference. ‖ ‖ step 6 ⋮ The recursive formula is $d(n) = d(n-1) + 16$ with $d(1) = 14$. ‖ ∻Answer∻ ⚹ $d(1) = 14$ and $d(n) = d(n-1) + 16$ ⚹ ∻Key Concept∻ ⚹Recursive Formula of an Arithmetic Sequence⚹ ∻Explanation∻ ⚹The recursive formula for an arithmetic sequence is given by $d(n) = d(n-1) + d$, where $d$ is the common difference between consecutive terms. The first term is specified as $d(1)$.⚹◊What is the common difference in the arithmetic sequence $14, 30, 46, 62, \ldots$?⍭ Generate me a similar question◊

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