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Mathway | Calculus Problem
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Let J(x)J(x) nave the ronowing grapn:
(a) Compute the limit limx0.7xf(x)\lim _{x \rightarrow 0.7} x f(x).
(b) Compute limx2.5x2f(x)\lim _{x \rightarrow 2.5} x^{2} f(x). How does this compare to the function g(x)=xf(x)g(x)=x f(x) evaluated at x=2.5x=2.5 ?
(c) Does the limit limz1.5f(x)x1.5\lim _{z \rightarrow 1.5} \frac{f(x)}{x-1.5} exist? Explain why or why not.
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Answer from Sia
Posted 5 months ago
Solution by Steps
step 1
To compute the limit as x x approaches 0.7 0.7 of xf(x) x f(x) , we evaluate limx0.7xf(x) \lim_{x \to 0.7} x f(x) . The value of f(0.7) f(0.7) can be determined from the graph
step 2
For the limit limx2.5x2f(x) \lim_{x \to 2.5} x^2 f(x) , we find f(2.5) f(2.5) from the graph and then compute 2.52f(2.5) 2.5^2 f(2.5) . This will give us the value of the limit
step 3
To compare this with g(x)=xf(x) g(x) = x f(x) evaluated at x=2.5 x = 2.5 , we calculate g(2.5)=2.5f(2.5) g(2.5) = 2.5 f(2.5) and compare the two results
step 4
For the limit limx1.5f(x)x1.5 \lim_{x \to 1.5} \frac{f(x)}{x - 1.5} , we need to check if f(x) f(x) approaches 0 0 as x x approaches 1.5 1.5 . If f(1.5)=0 f(1.5) = 0 , then the limit exists; otherwise, it does not
Answer
The limits and comparisons will depend on the specific values of f(x) f(x) at the points of interest from the graph.
Key Concept
Understanding limits and their evaluation using graphical information is crucial in calculus.
Explanation
The limits help us understand the behavior of functions at specific points, and comparing different functions at those points provides insight into their relationships.

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