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Biology
Posted 10 months ago
An aminoglycoside complexed with copper has been shown to cleave DNA and can potentially be used as an antitumor agent. The glycoside cleaves DNA at a rate of 3.57 h13.57 \mathrm{~h}^{-1} whereas the uncatalyzed rate of DNA hydrolysis is 3.6×108 h13.6 \times 10^{-8} \mathrm{~h}^{-1}. What is the rate enhancement for DNA cleavage by the aminoglycoside?
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Answer from Sia
Posted 10 months ago
Answer
The rate enhancement for DNA cleavage by the aminoglycoside is 9.92×1069.92 \times 10^6 times faster than the uncatalyzed rate.
Solution
a
Calculate the rate enhancement by dividing the catalyzed rate by the uncatalyzed rate: Rate enhancement=Catalyzed rateUncatalyzed rate\text{Rate enhancement} = \frac{\text{Catalyzed rate}}{\text{Uncatalyzed rate}}
b
Substitute the given rates into the formula: Rate enhancement=3.57h13.6×108h1\text{Rate enhancement} = \frac{3.57 \, \mathrm{h}^{-1}}{3.6 \times 10^{-8} \, \mathrm{h}^{-1}}
c
Perform the division to find the rate enhancement: Rate enhancement=9.92×106\text{Rate enhancement} = 9.92 \times 10^6
Key Concept
Rate enhancement is the factor by which a catalyst increases the rate of a reaction compared to the uncatalyzed rate.
Explanation
The rate enhancement is calculated by dividing the rate of the catalyzed reaction by the rate of the uncatalyzed reaction, providing a measure of the catalytic efficiency of the aminoglycoside.

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