A woman with ex linked color blindness and Turner syndrome had a colorblind father and a mother without medical records of having any of these two conditions and which of her parents. did non-disjunction of the sex chromosomes occur is the genotype of the woman?

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Accepted Answer

∻Answer∻ ⚹ The woman has one X chromosome with the color blindness allele and no Y chromosome due to non-disjunction in her mother. ⚹ ∻Solution∻ ‖ a ⋮ Color blindness inheritance: Color blindness is an X-linked recessive trait. A woman with color blindness must have received one allele for color blindness from her father. ‖ ‖ b ⋮ Turner syndrome inheritance: Turner syndrome occurs when a female has only one X chromosome (X0). This is typically the result of non-disjunction during gamete formation in one of the parents. ‖ ‖ c ⋮ Non-disjunction occurrence: Since the father is colorblind, he has only X chromosomes with the color blindness allele to pass on. The mother must have had non-disjunction occur during meiosis, leading to an egg with no sex chromosome (0) that was fertilized by a sperm carrying an X chromosome with the color blindness allele. ‖ ‖ d ⋮ Genotype of the woman: The woman's genotype is Xc0, where Xc represents the X chromosome with the color blindness allele, and 0 represents the absence of a second sex chromosome. ‖ ∻Key Concept∻ ⚹ X-linked inheritance and non-disjunction ⚹ ∻Explanation∻ ⚹ The woman's color blindness was inherited from her father, and her Turner syndrome resulted from non-disjunction in her mother, leading to a 45,Xc genotype. ⚹◊How does Turner syndrome impact the inheritance of sex-linked conditions such as color blindness?⍭ Generate me a similar question◊

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