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Question
Math
Posted 10 months ago

A set of average city temperatures in July are normally distributed with a mean of 23.5C23.5^{\circ} \mathrm{C} and a standard deviation of 2C2^{\circ} \mathrm{C}. The average temperature of Rabat is 23C23^{\circ} \mathrm{C}.

What proportion of average city temperatures are higher than that of Rabat?
You may round your answer to four decimal places.
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Answer from Sia
Posted 10 months ago
Solution by Steps
step 1
Calculate the z-score for Rabat's average temperature
step 2
The z-score is calculated using the formula z=Xμσz = \frac{X - \mu}{\sigma}, where XX is Rabat's temperature, μ\mu is the mean temperature, and σ\sigma is the standard deviation
step 3
Substituting the given values, we get z=2323.52=0.25z = \frac{23 - 23.5}{2} = -0.25
step 4
Look up the z-score in the standard normal distribution table or use a calculator to find the proportion of the area to the right of this z-score
step 5
The area to the right of z=0.25z = -0.25 corresponds to the proportion of average city temperatures higher than that of Rabat
step 6
Using the standard normal distribution table or a calculator, we find that the area to the right of z=0.25z = -0.25 is approximately 0.5987
Answer
The proportion of average city temperatures higher than that of Rabat is approximately 0.5987.
Key Concept
Z-score and Normal Distribution
Explanation
The z-score represents the number of standard deviations a data point is from the mean. In a normal distribution, the area to the right of a negative z-score represents the proportion of data points that are higher than the given value

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