A radioactive isotope undergoes beta plus decay. The remaining daughter isotope is $\mathrm{O}-18$.

What was the identity of the parent isotope?

Choose 1 answer:
(A) $\mathrm{N}-18$
(B) F-18
(c) $\mathrm{Ne}-22$

Question

A radioactive isotope undergoes beta plus decay. The remaining daughter isotope is $\mathrm{O}-18$.

What was the identity of the parent isotope?

Choose 1 answer:
(A) $\mathrm{N}-18$
(B) F-18
(c) $\mathrm{Ne}-22$

Accepted Answer

***B*** ∻Key Concept∻ ⚹Beta plus decay⚹ ∻Explanation∻ ⚹In beta plus decay, a proton is converted into a neutron, a positron, and a neutrino. The atomic number decreases by one while the mass number remains the same. For $^{18}\mathrm{O}$ to be the daughter isotope, the parent isotope must have one more proton, which is $^{18}\mathrm{F}$.⚹◊What is the chemical equation for beta plus decay in the context of radioisotopes?⍭ Generate me a similar question◊

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