A lab group prepares a $0.50 \mathrm{~L}$ solution of $0.35 \mathrm{M} \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}$. They accidentally leave the solution uncovered overnight and return to find its volume decreased to $0.47 \mathrm{~L}$.

What is the new molarity of the $\mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}$ solution?
Report your answer to two decimal places.
$\square$ $\mathrm{M} \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}$

Question

A lab group prepares a $0.50 \mathrm{~L}$ solution of $0.35 \mathrm{M} \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}$. They accidentally leave the solution uncovered overnight and return to find its volume decreased to $0.47 \mathrm{~L}$.

What is the new molarity of the $\mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}$ solution?
Report your answer to two decimal places.
$\square$ $\mathrm{M} \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}$

Accepted Answer

∻Solution∻ ‖ 1 ⋮ **Calculate the initial moles of solute**: The initial moles of $ \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2} $ can be calculated using the formula $ \text{moles} = \text{molarity} \times \text{volume} $. Given the initial molarity is $0.35 \, \mathrm{M}$ and the initial volume is $0.50 \, \mathrm{L}$, we have: $$ \text{moles of } \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2} = 0.35 \, \mathrm{M} \times 0.50 \, \mathrm{L} = 0.175 \, \text{moles} $$ ‖ ‖ 2 ⋮ **Determine the new volume**: The new volume of the solution is given as $0.47 \, \mathrm{L}$. ‖ ‖ 3 ⋮ **Calculate the new molarity**: The new molarity can be found using the formula $ \text{molarity} = \frac{\text{moles}}{\text{volume}} $. Using the moles calculated in step 1 and the new volume: $$ \text{new molarity} = \frac{0.175 \, \text{moles}}{0.47 \, \mathrm{L}} \approx 0.37 \, \mathrm{M} $$ ‖ ∻Answer∻ ⚹ 0.37 M ⚹ ∻Key Concept∻ ⚹ Molarity is the number of moles of solute per liter of solution. ⚹ ∻Explanation∻ ⚹ The molarity of a solution changes when the volume of the solution changes, provided the amount of solute remains constant. By calculating the initial moles of solute and dividing by the new volume, we determine the new molarity. ⚹◊What is the formula to calculate molarity of a solution?⍭ Generate me a similar question◊

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