A hypothetical stable element, $U$, with an atomic number of 150 , forms a binary compound with hydrogen, known as hydride UH_n. This hydride is discovered to have remarkable thermal stability and an unusually high hydrogen content. Given the periodic trends and chemical principles, what is the most likely value of $n$ in UH_n, and how does the U-H bonding in UH_n primarily occur? Options: a) $n=2$, with bonding occurring through conventional sp hybridization. b) $n=4$, with bonding involving $d$-orbitals and metallic character. c) $n=6$, with bonding facilitated by expanded octet and multi-center bonding. d) $n=8$, with bonding predominantly ionic due to the high electropositivity of $U$.

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***C*** ∻Key Concept∻ ⚹Expanded Octet and Multi-center Bonding⚹ ∻Explanation∻ ⚹Elements with atomic numbers greater than 120 are predicted to exhibit unusual chemical properties due to relativistic effects. For an element with an atomic number of 150, conventional bonding theories such as sp hybridization or d-orbital involvement may not be sufficient to describe its bonding behavior. The high atomic number suggests that the element could accommodate more electrons than the typical octet rule allows. This leads to the possibility of an expanded octet and multi-center bonding, which can stabilize a high hydrogen content in a hydride, as in UH₆.⚹◊Based on the information provided, what elements are likely involved in the U-H bonding in the compound UH_n?⍭ Generate me a similar question◊

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