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charityliu21's Question
Physics M
Posted 5 months ago

A 51.0 kg skier skis directly down a frictionless slope angled at 10.010.0^{\circ} to the horizontal. Choose the positive direction of the xx-axis to be downhill along the slope. A wind force with component FxF_{x} acts on the skier. What is FxF_{x} if the magnitude of the skier's velocity is (a) constant, (b) increasing at a rate of 1.00 m/s21.00 \mathrm{~m} / \mathrm{s}^{2}, and (c) increasing at a rate of 2.00 m/s22.00 \mathrm{~m} / \mathrm{s}^{2}.
(a) Number
i
Units \square
(b) Number
i
Units \square
(c) Number
i
Units \square
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Answer from Sia
Posted 5 months ago
Solution
a
For the skier to have a constant velocity, the net force acting on the skier must be zero. Therefore, the wind force component must balance the component of gravitational force acting down the slope. The gravitational force component along the slope is given by Fg,x=mgsin(θ)F_{g,x} = mg \sin(\theta), where m=51.0kgm = 51.0 \, \text{kg} and g=9.81m/s2g = 9.81 \, \text{m/s}^2. Thus, the wind force is Fx=mgsin(10.0)F_x = mg \sin(10.0^{\circ}). Calculating this gives: Fx=51.0×9.81×sin(10.0)8.73NF_x = 51.0 \times 9.81 \times \sin(10.0^{\circ}) \approx 8.73 \, \text{N}
b
If the skier is accelerating at a rate of 1.00m/s21.00 \, \text{m/s}^2, we apply Newton's second law: Fnet=maF_{net} = ma. The net force is the difference between the gravitational force component and the wind force: Fnet=mgsin(10.0)FxF_{net} = mg \sin(10.0^{\circ}) - F_x. Setting this equal to mama gives us: Fx=mgsin(10.0)maF_x = mg \sin(10.0^{\circ}) - ma. Substituting the values, we find: Fx=51.0×9.81×sin(10.0)51.0×1.007.73NF_x = 51.0 \times 9.81 \times \sin(10.0^{\circ}) - 51.0 \times 1.00 \approx 7.73 \, \text{N}
c
For an acceleration of 2.00m/s22.00 \, \text{m/s}^2, we use the same approach as in part (b). The equation becomes: Fx=mgsin(10.0)maF_x = mg \sin(10.0^{\circ}) - ma. Substituting the values gives: Fx=51.0×9.81×sin(10.0)51.0×2.006.73NF_x = 51.0 \times 9.81 \times \sin(10.0^{\circ}) - 51.0 \times 2.00 \approx 6.73 \, \text{N}
Answer
(a) 8.73 N
 (b) 7.73 N 
(c) 6.73 N
Key Concept
Newton's Second Law: The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Equation: F=maF = ma (Net force equals mass times acceleration)
Explanation
The calculations for each scenario involve balancing the forces acting on the skier, using the gravitational force component and the wind force to determine the required force for constant or varying acceleration.

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