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Question
Computer Science
Posted 9 months ago

6. Determine the truth value of each statement
(a) Artly (x2 
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Answer from Sia
Posted 9 months ago
Sure, let's determine the truth value of each statement given the specified domains.

 Question 6(a)
xy(x2<y+1) domain: R×R\forall x \forall y (x^2 < y + 1) \text{ domain: } \mathbb{R} \times \mathbb{R}

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Answer Choice:
False

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Key Concept
Universal Quantifier

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Explanation
For all xx and yy in R\mathbb{R}, x2<y+1x^2 < y + 1 is not true because you can always find an xx such that x2x^2 is greater than any given y+1y + 1.


 Question 6(b)
xy(xy) domain: Z+×Z+\forall x \forall y (x \leq y) \text{ domain: } \mathbb{Z}^+ \times \mathbb{Z}^+

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Answer Choice:
False

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Key Concept
Universal Quantifier

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Explanation
For all xx and yy in Z+\mathbb{Z}^+, xyx \leq y is not true because you can always find xx and yy such that x>yx > y.


 Question 6(c)
xy(xy) domain: Z+×Z+\exists x \forall y (x \leq y) \text{ domain: } \mathbb{Z}^+ \times \mathbb{Z}^+

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Answer Choice:
False

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Key Concept
Existential and Universal Quantifiers

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Explanation
There does not exist an xx in Z+\mathbb{Z}^+ such that xyx \leq y for all yy in Z+\mathbb{Z}^+. For example, if x=1x = 1, there exists y=2y = 2 such that 121 \leq 2 is true, but if x=2x = 2, 212 \leq 1 is false.


 Question 6(d)
x(x2<x) domain: Z+\exists x (x^2 < x) \text{ domain: } \mathbb{Z}^+

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Answer Choice:
False

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Key Concept
Existential Quantifier

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Explanation
For xx in Z+\mathbb{Z}^+, x2<xx^2 < x is never true because x2x^2 is always greater than or equal to xx for all positive integers.


 Question 6(e)
x(x2<x) domain: R\exists x (x^2 < x) \text{ domain: } \mathbb{R}

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Answer Choice:
True

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Key Concept
Existential Quantifier

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Explanation
For xx in R\mathbb{R}, there exist values such as 0<x<10 < x < 1 where x2<xx^2 < x is true. For example, if x=0.5x = 0.5, then 0.52=0.25<0.50.5^2 = 0.25 < 0.5.

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