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aaronhou's Question
Math
Posted 11 months ago
correct and helpful
(3) limxasinxsinaxa\lim _{x \rightarrow a} \frac{\sin x-\sin a}{x-a};
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Answer from Sia
Posted 11 months ago
Solution by Steps
step 1
Apply L'Hôpital's Rule since the limit is of the indeterminate form 00\frac{0}{0}
step 2
Differentiate the numerator and the denominator with respect to xx
step 3
The derivative of sin(x)\sin(x) is cos(x)\cos(x), and the derivative of xx is 11
step 4
Substitute xx with aa in the derivative of the numerator
step 5
The limit becomes limxacos(x)1=cos(a)\lim_{x \to a} \frac{\cos(x)}{1} = \cos(a)
Answer
cos(a)\cos(a)
Key Concept
L'Hôpital's Rule for Indeterminate Forms
Explanation
When faced with a limit that results in an indeterminate form such as 00\frac{0}{0}, L'Hôpital's Rule can be applied by taking the derivative of the numerator and the denominator separately and then evaluating the limit.

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