2. What is the number of hydroxide ions, $\mathrm{OH}$ present in $0.7 \mathrm{~mol}$ of iron (III) hydroxide, $\mathrm{Fe}(\mathrm{OH})_{3}$ ?

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***D*** ∻Key Concept∻ ⚹Stoichiometry and Mole Calculations⚹ ∻Explanation∻ ⚹To find the number of hydroxide ions in 0.7 mol of $Fe(OH)_3$, we need to recognize that each formula unit of $Fe(OH)_3$ contains 3 hydroxide ions ($OH^-$). Therefore, the number of hydroxide ions is $0.7 ext{ mol} imes 3 = 2.1 ext{ mol}$ of $OH^-$ ions.⚹◊Can you calculate the molar mass of iron (III) hydroxide, $\mathrm{Fe(OH)_{3}}⍭ Generate me a similar question◊

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