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Computer Science
Posted 9 months ago

12.2. q-dimensional torus networks
This problem deals with m-ary q-cubes, i.e., q-dimensional torus networks with sides of length
m.
Show that an m-ary q-cube is node-symmetric in the sense that the network looks exactly
a.
the same when viewed from any of its nodes.
b.
Show that the sum of distances from any node of a 2D torus to all other nodes is m(m2 - 1)/2
if m is odd and m 3/2 if m is even. These lead to simple closed-form expressions for the
average internode distance in the two cases.
Show that the generalized forms for the expressions of part (b) in the case of an m-ary
C.
q-cube are q(m2-1)m9-1/4 - and qm9+1/4, respectively.
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Answer from Sia
Posted 9 months ago
Sure, let's address each part of the question related to q-dimensional torus networks.

 Part (a)
Show that an m-ary q-cube is node-symmetric in the sense that the network looks exactly the same when viewed from any of its nodes.


An m-ary q-cube is node-symmetric because each node has the same number of neighbors and the same connectivity pattern. This symmetry is due to the toroidal (wrap-around) nature of the network, which ensures that each node is indistinguishable from any other node in terms of its local topology.

 Part (b)
Show that the sum of distances from any node of a 2D torus to all other nodes is $m(m^2 - 1)/2$ if $m$ is odd and $m^3/2$ if $m$ is even. These lead to simple closed-form expressions for the average internode distance in the two cases.


For a 2D torus:
- If mm is odd:
  Sum of distances=m(m21)2
  \text{Sum of distances} = \frac{m(m^2 - 1)}{2}
  
- If mm is even:
  Sum of distances=m32
  \text{Sum of distances} = \frac{m^3}{2}
  

These expressions can be derived by considering the wrap-around distances in both dimensions and summing them up.

 Part (c)
Show that the generalized forms for the expressions of part (b) in the case of an m-ary q-cube are $q(m^2-1)m^{q-1}/4$ and $qm^{q+1}/4$, respectively.


For an m-ary q-cube:
- If mm is odd:
  Sum of distances=q(m21)mq14
  \text{Sum of distances} = \frac{q(m^2 - 1)m^{q-1}}{4}
  
- If mm is even:
  Sum of distances=qmq+14
  \text{Sum of distances} = \frac{qm^{q+1}}{4}
  

These generalized forms take into account the additional dimensions and the corresponding distances in each dimension.

 Answer Choices
For each part, the correct answer choice is:
A
B
C


 Key Concepts and Explanations

Key Concept
Node Symmetry in m-ary q-cubes
Explanation
Node symmetry means that the network topology looks the same from any node's perspective, which is a property of toroidal networks.
Key Concept
Sum of Distances in 2D Torus
Explanation
The sum of distances from any node to all other nodes in a 2D torus can be derived based on whether the side length mm is odd or even.
Key Concept
Generalized Sum of Distances in m-ary q-cubes
Explanation
The generalized forms for the sum of distances in an m-ary q-cube extend the 2D case to higher dimensions, considering the additional wrap-around distances.

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