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jack78375's Question
Biology
Posted 10 months ago
10 Find the values of aa and bb and factorise the polynomial P(x)=x3+ax2x+bP(x)=x^{3}+a x^{2}-x+b, given that P(x)P(x) is divisible by x1x-1 and x+3x+3.
11 a Show that xax-a is a factor of xnanx^{n}-a^{n}, for any constant aa and any natural number nn.
b Find conditions (if any) on nn that are required in order that:
i x+ax+a is a factor of xn+anx^{n}+a^{n}
ii x+ax+a is a factor of xnanx^{n}-a^{n}.
12 The polynomial P(x)P(x) has a remainder of 2 when divided by x1x-1 and a remainder of 3 when divided by x2x-2. The remainder when P(x)P(x) is divided by (x1)(x2)(x-1)(x-2) is ax+ba x+b, i.e. P(x)P(x) can be written as P(x)=(x1)(x2)Q(x)+ax+bP(x)=(x-1)(x-2) Q(x)+a x+b.
a Find the values of aa and bb.
b i Given that P(x)P(x) is a cubic polynomial with coefficient of x3x^{3} being 1 , and -1 is a solution of the equation P(x)=0P(x)=0, find P(x)P(x).
ii Show that the equation P(x)=0P(x)=0 has no other real solutions.
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Answer from Sia
Posted 10 months ago
Hi Jack78375! It looks like you have a few questions about polynomial factorization and remainders. Let's start with the first part of your question. To find the values of a and b and factorize the polynomial P(x), we can use the given information that P(x) is divisible by (x-1) and (x+3). This means that (x-1) and (x+3) are factors of P(x). We can use polynomial long division or synthetic division to find the quotient and then factorize the polynomial. Let's work through this step by step.

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