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isabella09132960's Question
Math
Posted 8 months ago

1. Double cover
A sheet of paper is exactly the same size as a rectangular table top. The paper is cut in half and the two halves are placed on the table as shown.
What is the ratio of the area of table left uncovered to the area that is covered twice?
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Answer from Sia
Posted 8 months ago
Solution by Steps
step 1
Let the area of the table top be AA. Since the paper is cut in half, each piece of paper has an area of A2\frac{A}{2}
step 2
When the two pieces of paper are placed on the table as shown, they overlap to cover a square section in the middle. The area of this overlap is A4\frac{A}{4} because each piece of paper covers half of the table, and the overlap is half of one piece of paper
step 3
The area covered twice is A4\frac{A}{4}
step 4
The area left uncovered is the total area of the table minus the area covered by the two pieces of paper. Since each piece of paper covers A2\frac{A}{2}, the total area covered by the two pieces of paper is AA. Therefore, the area left uncovered is AA=0A - A = 0
step 5
However, since the pieces of paper overlap, the area covered twice is A4\frac{A}{4}, and the area left uncovered is A(A2+A2A4)=A(AA4)=A4A - \left(\frac{A}{2} + \frac{A}{2} - \frac{A}{4}\right) = A - \left(A - \frac{A}{4}\right) = \frac{A}{4}
step 6
The ratio of the area left uncovered to the area covered twice is A4A4=1\frac{\frac{A}{4}}{\frac{A}{4}} = 1
Answer
The ratio of the area left uncovered to the area covered twice is 1.
Key Concept
Ratio of areas
Explanation
The key concept here is understanding how to calculate the areas of the table that are left uncovered and covered twice, and then finding the ratio of these areas.

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