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ORG CHEM I · Structure, mechanisms, SN/E reactions
Midterm & Final Reference · Ultra-Dense A4
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STRUCTURE & HYBRIDIZATION ↗ TAP
Hybridization at a glance
TypeGeometryAngleπ bondsExample
sp³tetrahedral109.5°0CH₄, C–C single
sp²trigonal planar120°1C=C, benzene, C=O
splinear180°2C≡C, C≡N, allene C
Steric # = (σ bonds) + (lone pairs) → sp³ if 4, sp² if 3, sp if 2
Bond order matters
σ vs π bonds
σ = head-on overlap, free rotation. π = sideways p-orbital overlap, locks geometry. Single = 1σ; double = 1σ + 1π; triple = 1σ + 2π.
Bond length / strength
Shorter is stronger: triple < double < single. C≡C (120 pm) < C=C (134) < C–C (154).

s-character determines acidity of C–H: more s = more electronegative C = more acidic. sp (50% s) > sp² (33%) > sp³ (25%). Terminal alkyne C–H pKa ≈ 25; alkane C–H ≈ 50.

Skeletal: each vertex = C, lines = bonds, H implicit to fill octet
⚡ EXAM TRAP — LONE PAIRS COUNT IN STERIC #

To find hybridization, count σ bonds + lone pairs, not just atoms attached. NH₃ has 3 bonds + 1 LP = 4 = sp³. H₂O has 2 bonds + 2 LP = 4 = sp³ (bent shape). Forgetting lone pairs assigns wrong geometry.

ACID-BASE, RESONANCE & ENERGY DIAGRAMS ↗ TAP
The 4 stabilizers (memorize)

To compare conjugate-base stability (= acid strength), check in this order: A·R·I·O.

FactorWhat it doesExample
Atom (size + EN)down a column: bigger = more stable; across: more EN = more stableHI > HBr > HCl > HF
Resonancespreads charge over more atomsRCOO⁻ vs RO⁻
InductiveEN groups withdraw e⁻ densityCCl₃COOH > CH₃COOH
Orbital (s-character)more s = more stable anionHC≡CH (sp) > H₂C=CH₂ (sp²)
pKa = −log Ka lower pKa = stronger acid ΔpKa > 4: rxn favors weaker acid
Resonance rules
Move only π or LP
Single bonds, σ, and atoms don't move between resonance structures. Only π electrons and lone pairs slide.
Major contributor
Most stable structure = lowest formal charge separation, charge on most-EN atom, full octets everywhere.

Energy diagrams: y-axis = potential energy. Hill = transition state; valleys = intermediates. Highest hill = rate-determining step. ΔG = product − reactant; activation energy = peak − reactant.

⚡ EXAM TRAP — RESONANCE ≠ MOVING ATOMS

Drawing a 'resonance structure' that moves H or C is a tautomer, not a resonance contributor. Real resonance keeps σ-framework frozen. Only π / LP / charge migrate. Drawing illegal arrows costs the entire problem.

STEREOCHEMISTRY ↗ TAP
Chirality basics

A chiral center = sp³ carbon with 4 different substituents. Chiral molecules are non-superimposable on their mirror image.

2ⁿ stereoisomers max for n chiral centers (less if symmetry)
R / S assignment
▼ ASSIGN R / S IN 4 STEPS

1. CIP priority by atomic number (higher Z = higher priority).

2. If tie at first atom, work outward — first point of difference wins.

3. Lowest priority pointing AWAY: read 1→2→3.

4. Clockwise = R, counterclockwise = S. If lowest is toward you, reverse.

TermDefinition
Enantiomersnon-superimposable mirror images (R/S inverted at all centers)
Diastereomersstereoisomers, NOT mirror images
Mesohas chiral centers BUT internal mirror plane → achiral
Racemic50:50 mix of enantiomers → no optical rotation
E / Z for alkenes
If higher-priority groups on same side: Z (zusammen). Opposite sides: E (entgegen). Replaces cis/trans for asymmetric alkenes.
Optical rotation
(+) clockwise, (−) counterclockwise. R/S labels are independent of (+)/(−) sign — no shortcut.
⚡ EXAM TRAP — LOWEST PRIORITY POSITION

If the lowest-priority group points toward you (out of page), the visible 1→2→3 rotation is opposite the true R/S. Reverse what you see. Most R/S errors come from skipping this check.

ALKENE / ALKYNE REACTIONS ↗ TAP
Markovnikov addition

H–X across C=C: H goes to the carbon with more H's (less substituted). X goes to the more substituted C (forms the more stable carbocation).

CH₃CH=CH₂ + HBr → CH₃CHBrCH₃ (2° carbocation, not 1°)
Reaction toolbox
ReagentAddsRegio / stereo
HX (HCl, HBr, HI)H + XMarkovnikov
HBr + ROOR (peroxide)H + Branti-Mark (radical)
H₂O, H₂SO₄H + OHMarkovnikov
BH₃ then H₂O₂/OH⁻H + OHanti-Mark, syn
Br₂, Cl₂X + Xanti addition
Br₂ / H₂OOH + BrMark, anti (halohydrin)
OsO₄ / KMnO₄ cold2 OHsyn diol
O₃ / Zncleaves C=C2 carbonyls
H₂ / Pd or Pt2 Hsyn, full reduction
Carbocation stability
3° > 2° > 1° > methyl. Hyperconjugation + induction from alkyl groups stabilizes positive C. Drives Markovnikov.
Watch for rearrangements
Cations can 1,2-shift H or alkyl to a more stable carbon. Especially common with H–X across alkenes adjacent to a 3° C.

Alkynes add twice if reagent is in excess (alkyne → alkene → alkane). With H₂O / H₂SO₄ / Hg²⁺: Markovnikov hydration gives a ketone (via enol tautomerization).

⚡ EXAM TRAP — PEROXIDE FLIPS Br ONLY

HBr + peroxide reverses regiochemistry to anti-Markovnikov via radicals. This only works for HBr — HCl and HI don't follow it. Many students apply 'peroxide rule' to all H-X. Wrong.

NMR & IR BASICS ↗ TAP
¹H NMR — what each axis means
FeatureTells you
chemical shift δ (ppm)chemical environment (electron density)
# of signalsnumber of distinct H environments
integrationrelative # of H's per signal
multiplicity (n+1 rule)number of neighboring H's: doublet → 1 nbr, triplet → 2, quartet → 3
δ ranges: alkyl ~1, OH/NH ~2-5 broad, aromatic 6-8, aldehyde 9-10, COOH 10-13
IR — functional group fingerprints
Most diagnostic peaks
O-H broad 3200–3600. N-H sharp 3300. C=O strong sharp 1700–1750 (sharper acid; lower aldehyde). C≡C / C≡N 2100–2260.
Fingerprint region
Below 1500 cm⁻¹ — unique to each compound but hard to interpret. Match to known spectra rather than predict.

¹³C NMR: shows # of unique C environments. Ranges: alkyl 0-50, alkene 100-140, aromatic 120-140, carbonyl 170-220.

DEPT: distinguishes CH (up), CH₂ (down), CH₃ (up); quaternary C invisible.

⚡ EXAM TRAP — n+1 RULE COUNTS NEIGHBORS, NOT SELF

For –CH₂–CH₃: the CH₂ sees 3 H's on the CH₃ → quartet (3+1). The CH₃ sees 2 H's on the CH₂ → triplet (2+1). You don't count your own H's. Off-by-one multiplicities lose questions.

SN1 vs SN2 ↗ TAP
Two pathways
FeatureSN2SN1
Mechanism1 step, concerted2 steps via carbocation
Rate lawk[R-X][Nu]k[R-X] only
Substrate1° > 2° > 3°3° > 2° > 1°
Nucleophilestrong, anionicweak, neutral
Solventpolar aprotic (DMSO, acetone)polar protic (H₂O, ROH)
Stereocheminversion (Walden)racemization (mix R/S)
Leaving groupbetter LG = faster (both)better LG = faster (both)
SN2 rate = k [substrate][Nu] SN1 rate = k [substrate]
Picking the right one
Substrate decides first
Methyl / 1° → SN2 only. 3° → SN1 only (steric blocks SN2). 2° → either, depends on Nu and solvent.
Nu strength + solvent
Strong Nu + aprotic → push SN2. Weak Nu + protic (often the solvent itself acts as Nu) → SN1.

Leaving-group ability: stable as anion. Best: I⁻ > Br⁻ > Cl⁻ > TsO⁻ >> F⁻ ≈ HO⁻. Use OTs (tosylate) when you need a great LG on an alcohol.

⚡ EXAM TRAP — STERICS KILL SN2 ON 3°

SN2 needs backside attack — tertiary carbons are too crowded. Even with a great Nu, 3° won't go SN2. Reverse trap: 1° won't go SN1 (cation too unstable). Match substrate to mechanism first, every time.

E1 vs E2 ↗ TAP
Two paths to alkene
FeatureE2E1
Steps1 (concerted)2 via cation
Ratek[R-X][base]k[R-X]
Substrate3° > 2° > 1°3° > 2° >> 1°
Basestrong (NaOEt, t-BuOK, DBU)weak / solvent
Geometry req.anti-periplanar H and LG (180°)none
RegioselectivityZaitsev (most subst alkene); Hofmann with bulky baseZaitsev
Zaitsev: removes H from the C with FEWEST H's → more substituted alkene
The E2 anti-periplanar requirement
Why anti
The C-H σ bond and C-LG σ bond must align antiparallel for orbital overlap. In a chair, the H and LG must both be axial. Otherwise no E2.
Bulky base = Hofmann
t-BuOK or DBU can't reach hindered H's, so removes the most accessible (least substituted) H → Hofmann product.

SN vs E competition: heat + strong base favors E. 1° + strong nonbulky Nu → SN2 wins. 3° + strong base → E2. 3° + weak base → SN1/E1 mix.

⚡ EXAM TRAP — E2 AND CYCLOHEXANES

For E2 on a cyclohexane, the H and LG must both be axial. Sometimes the only axial-axial geometry forces removal of a less-favored H — Zaitsev violated by stereochemistry. Always draw the chair.

DECISION BOX — PICK THE MECHANISM ↗ TAP
Substitution / elimination flowchart
SubstrateConditionsMechanism
Methyl, 1°Strong Nu, polar aproticSN2
Methyl, 1°Strong base, heatE2 (rare for 1°, except bulky base)
Strong Nu, polar aproticSN2
Strong base, polar aprotic, heatE2
Weak Nu, polar proticSN1 + E1 mix
Strong Nu (rare)E2 (SN2 blocked)
Weak Nu, polar protic, heatSN1 + E1 mix
Strong bulky base (t-BuOK)E2, Hofmann
Reagent recognition
Reagent / clueUse § from
HX adds to alkene → Markovnikov§ ⑤
HBr + peroxide → anti-Markovnikov§ ⑤
BH₃ then H₂O₂ → anti-Mark, syn OH§ ⑤
OsO₄ or cold KMnO₄ → syn diol§ ⑤
O₃ then Zn → cleave C=C to carbonyls§ ⑤
broad O-H ~3200-3600 cm⁻¹ + sharp C=O ~1710 → COOH§ ⑦
quartet ~4 ppm + triplet ~1 ppm → ethyl group adjacent to O§ ⑦
'rank acidity'§ ⑥A·R·I·O analysis on conjugate base
Recognize hybridization first
Geometry / bond angles / acidity all flow from sp/sp²/sp³. Steric # = σ + LP. π bonds don't count.
Stereochem checklist
Chiral centers? E/Z? Meso possible? Inversion / retention / racemization? Mark each on every product.
⚡ EXAM TRAP — REARRANGEMENT

Whenever the mechanism passes through a carbocation (SN1, E1, HX addition), watch for 1,2-H or 1,2-alkyl shifts to a more stable C⁺. The 'expected' product may be wrong because the cation rearranged before the Nu attacked.

⚡ FINAL EXAM TRAP — DRAW EVERY ARROW

Mechanisms earn partial credit per arrow. Always draw curved arrows from electron source to electron sink. Skipping arrow notation = losing 50% even with the right product.

ORG CHEM I · Comprehensive Cram Sheet · Ultra-Dense A4
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